Question

Area of rectange is 192sqm & perimetre is 56cm. find its length & breadth?

Answer 1

The area of a rectangle = l x b = 192 cm(sq) 
= l = 192/b 
The perimeter = 2l + 2b = 56 
= 2*(192/b) + 2b = 56 
= (384/b) +2(b^2) =384 
rearranging&dividing by 2 = b^2 - 28b + 192 =0 
= b^2 - 16b - 12b + 192 = 0 
= b(b - 16) - 12(b - 16) = 0 
= (b - 16) (b -12) =0 
so b-16=0 i.e b= 16 
or 
b-12 = 0 i.e b = 12 
if l = 12 then b = 16 or vice versa 

area = l * b = 12 * 16 = 192 
peri = (2 *12)+(2 * 16) = 24 +52 = 56