Area of rectangle ABCD in the figure is 36 cm2 what is the area of Triangle ABP
Answers
Answer:
18 cm²
Step-by-step explanation:
( Refer to attachment for figure)
Construction : Draw a perpendicular line to AB from P and name that as Q
a) Area of the rectangle ABCD = Length × Breadth = AB × CB = 36 cm²
AB × CB = 36 cm² ------ ( 1 )
Area of the ∆ABP = 1/2 × Base × Height
= 1/2 × AB × PQ
Since height of the triangle = Breadth of the rectangle, PQ = CB
= 1/2 × AB × CB
From eq( 1 )
= 36/2
= 18 cm²
Therefore the area of the ∆ ABP is 18 cm².
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Given:
Area of Reactangle ABCD = 36 cm².
To find:
Area of ∆ABP?
Calculation:
Area of Rectangle = 36 cm²
=> Length × Breadth = 36
=> AB × BC = 36 . . . . . (1)
We know that area of a ∆ is given as :
From the figure, we can see that base is AB and height is equal and parallel to BC.
So, area of ∆ = 18 cm².