Area of rectangle ABCD in the figure is 36 square find the size
Answers
Explanation:
Dreux Patch
The question asks
a) Area of ABCD
b) Area of triangle AEF
c) Length of BD
d) Perimeter of ABCD
For question
a)Area of ABCD:
We are finding the area of the rectangle Area=Base X Height
First you add the base lengths of the rectangle AF(7) and FD(3) together. This gives you the total base length of the rectangle, which you then multiply by the height.
(AF+FD)(AB)=Area
(7+3)(5)=50
b)Area of triangle AEF
We are finding the area of a triangle Area=1/2 Base X Height
First we plug in out known values
AF(7) is our base
We know the height of the rectangle (AB) is 5
It does not matter that the line is not part of our triangle it still gives the height information needed.
Area=1/2(AF)(AB)
Area=1/2(7)(5)
Area=17.5
c)Length of BD
We are finding the length of the hypotenuse a^2+b^2=c^2
From question a) we know the length of AD is 10 and the height of the triangle (AB) is 5.
Use this information to plug in the formula
a^2+b^2=c^2
10^2+5^2=c^2
100+25=c^2
125=c^2
square root both sides
c=11.18 or 5 squareroot(5
d)Perimeter of ABCD
We are finding the total length around the rectangle. The rectangle has four sides two heights and two widths Perimeter=2widths+2height
We know the height AB is 5 and the width AD is 10, plug this information into the formula.
Perimeter=2widths+2heights
Perimeter=2(10)+2(5)
Perimeter=20+10
Perimeter=30
Answer:
Area of the rectangle ABCD is 40 sq. cm.
Explanation:
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