Question

Area of rectangle if its sides are (3x – 4)m in and (4x – 3)m ?​

Answer 1

$\rm{Area\:of\:Rectangle = Length\times Breadth}$

$\longrightarrow\rm{Area\:of\:Rectangle = (3x-4)\:m\times (4x-3)\:m}$

$\longrightarrow\rm{Area\:of\:Rectangle = (3x-4)\times (4x-3)\:m^2}$

$\longrightarrow\rm{Area\:of\:Rectangle = 3x\times (4x-3)-4\times(4x-3)\:m^2}$

$\longrightarrow\rm{Area\:of\:Rectangle = 12x^2-9x-16x+12\:m^2}$

$\longrightarrow\rm{Area\:of\:Rectangle = 12x^2-25x+12\:m^2}$

Answer 2

Answer:

12x^2 - 25x + 12 answer

Step-by-step explanation:

Length of rectangle = (3x-4)

Breadth of rectangle = (4x-3)

area of rectangle = l*b

so, => (3x-4)*(4x-3)

= 12x^2 - 9x - 16x + 12

= 12x^2 - 25x + 12 answer.

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