Question

Area of rectangle is 192 cm²& its breath is 12 cm. Find the perimeter and the diagonal of the rectangle.​

Answer 1

Answer:

area=lb => 192=12l

=> l=16

diagonal of rectangle= root of l^2+b^2

= root of 400 = 20cm

hope it's helpful mark as brainlest answer

Answer 2

The perimeter and diagonal of rectangle is 56 cm and 20 cm respectively.

Given - Area and breadth

Find - Perimeter and diagonal

Solution - Firstly we need to find the length of rectangle using the formula -

Area = length × breadth

Length = $\frac{192}{12}$

Length = 16 cm

Now, finding the perimeter using the formula -

Perimeter = 2 × (length + breadth)

Perimeter = 2 × (16 + 12)

Perimeter = 2 × 28

Perimeter = 56 cm

Now, finding diagonal of rectangle by the formula-

Diagonal = $\sqrt{ {length}^{2} + {breadth}^{2} }$

Diagonal = $\sqrt{ {16}^{2} + {12}^{2} }$

Diagonal = $\sqrt{256 + 144}$

Diagonal = $\sqrt{400}$

Diagonal = 20 cm

Hence, the perimeter and diagonal of rectangle is 56 cm and 20 cm respectively.

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