area of rectangle is 21 metre square if the perimeter of the rectangle is 20 find the length and breadth of the rectangle.
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The length and breadth of the rectangle are 7m and 3m respectively.
We know that for a rectangle of length 'l' and breadth 'b', its area is given as lb
Similarly, its perimeter is given as 2(l+b)
Given, the area of the rectangle is 21 m²
So, lb = 21
⇒l = 21/b ...(1)
And, permineter = 20m
So, 2(l+b) = 20
⇒(l+b) = 10 ...(2)
Putting l = 21/b from (1) in (2),we get:
21/b + b = 10
Mutiplying with 'b' on both sides, we get:
21 + b² = 10b
⇒ b² - 10b + 21 = 0
⇒ b² - 7b - 3b + 21 = 0
⇒ b(b-7) - 3(b-7) = 0
⇒ (b-7)(b-3) = 0
By zero product rule,
When b = 7m
l = 10 - b = 3 m
This is absurd because, we know that length of a rectangle cannot be less than its breadth.
So, breadth = 3m
and, length = 10 - 3 = 7m
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