Question

Area of rectangle is 24 cm2 and perimeter 20 cm then their length of diagonal

Answer 1

Answer:

Diagonal = 7.21 cm

other two sides are 4 & 6 cm

Step-by-step explanation:

Let say side are  L & B cm

Area = LB = 24 cm^2

Perimeter =  2*(L+B) = 20

(L + B ) = 10

Squaring both sides

L^2 + B^2 + 2LB = 100

L^2 + B^2 + 48 = 100

L^2 + B^2 = 52

(Length of diagonal)^2 = L^2 + B^2

Length of diagonal = √52

Length of diagonal = 7.21 cm

Solving further

(L-B)^2 = L^2 + B^2 - 2LB

(L-B)^2 = 52 - 48

L-B = 4

L-B = +/- 2

case 1

L-B =2

L + B = 10

Adding both 2L = 12 so L = 6 cm

B = 4cm

Case 2

L - B = -2

L + B = 10

Adding both 2L = 8 so L = 4cm

B = 6 cm