area of rectangle is 27 and perimeter is 24 find the length and breadth
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Answered by
1
Lb=27..........(1)
2(l+b)=24
L+b=12
B=12-l
Put in (1)
(12-l)×l=27
12l-l^2=27
L^2-12l+27=0
L=3or9
B=30r9
2(l+b)=24
L+b=12
B=12-l
Put in (1)
(12-l)×l=27
12l-l^2=27
L^2-12l+27=0
L=3or9
B=30r9
Answered by
0
hi!!
it is given that 2(l+b)=24therefore l+b=12(i equation)
now it is also given that lb=27(2 eq)
therefore from i eq we have l=12-b
now put it in 2 eq
(12-b)b=27
12b-b*2=27
or
b*2-12b+27=0
b*2-9b-3b+27=0
b(b-9)-3(b-9)=0
(b-3)(b-9)=0
therefore b=3 or 9
therefore l=9 or 3
it is given that 2(l+b)=24therefore l+b=12(i equation)
now it is also given that lb=27(2 eq)
therefore from i eq we have l=12-b
now put it in 2 eq
(12-b)b=27
12b-b*2=27
or
b*2-12b+27=0
b*2-9b-3b+27=0
b(b-9)-3(b-9)=0
(b-3)(b-9)=0
therefore b=3 or 9
therefore l=9 or 3
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