area of rectangle is 80 square cm and length is 10 cm find its breadth and perimeter
Answers
Answer:
Breadth of the rectangle = 8cm
perimeter of the rectangle = 36 cm
Step-by-step explanation:
Given,
area of the rectangle = 80 sqcm
length = 10 cm
consider breadth as 'x'
area of the rectangle = (l×b)= 80 sqcm
(10)(b) = 80
b = 80/10
therefore, b = 8cm
perimeter of rectangle = 2 (l+b)
=2 (10+8)
=2 (18)
=36
Answer :
- Breadth of rectangle is 8cm
- Perimeter of rectangle is 36cm
Given :
- Area of rectangle is 80cm²
- Length of rectangle is 10cm
To find :
- Breadth of rectangle
- Perimeter of rectangle
Solution :
First we need to find the breadth of rectangle :
- Let the breadth of rectangle be x
- Length of rectangle is 10cm
- Area of rectangle is 80cm²
We know that
- Area of rectangle = l × b
Where,
- l is length of rectangle
- b is breadth of rectangle
↦ Area of rectangle = length × breadth
↦ 80 = 10 × b
↦ b = 80/10
↦ b = 8cm
Hence, Breadth of rectangle is 8cm.
Now , Finding the perimeter of rectangle :
Given,
- Length of rectangle is 10cm
- Breadth of rectangle is 8cm
We know that
- Perimeter of rectangle = 2(l + b)
Where,
- l is length of rectangle
- b is breadth of rectangle
↦ Perimeter of rectangle = 2(l + b)
↦ Perimeter of rectangle = 2(10 + 8)
↦ Perimeter of rectangle = 2(18)
↦ Perimeter of rectangle = 36cm
Perimeter of rectangle is 36cm.
Hence,
- Breadth of rectangle is 8cm
- Perimeter of rectangle is 36cm
Verification :
↦ Area of rectangle = length × breadth
↦ 80 = 10 × 8
↦ 80 = 80
Hence , Verified