Question

Area of rectangle is (x² 4x-45)sq units
and its breath is (x+5)units find its
length​

Answer 1

Answer:

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$\text{Area of rectangle = x^2-4x-45}$

We can solve it by middle term splitting...

=>$x^2-9x+5x-45$

=>$x(x+5)-9(x+5)$

=>$(x+5)(x-9)$

=>$\huge\orange{\fbox{\pink{\text{Length=x-9}}}}$

$\huge{\purple{\bigstar{\blue{\text{Hope it helps...}}}}}$

Answer 2

Area of the rectangle is x² + 2x - 15 sq. units

Let's solve this quadratic equation by splitting the middle term method ,

⇒ x² + 2x - 15

⇒ x² - 3x + 5x - 15

⇒ x (x - 3) + 5 (x - 3)

⇒ (x - 3) (x + 5)

Length of the rectangle = x + 5 units

Breadth of the rectangle = ? units

We know that , " Area of the rectangle is defined as product of length and breadth "

$:\implies \sf Area_{Rectangle}=Length\times Breadth$

$:\implies \sf x^2+2x-15=(x+5)\times Breadth$

$:\implies \sf (x-3)(x+5)=(x+5)\times Breadth$

$:\implies \sf (x-3)=Breadth$

$:\implies \sf \purple{Breadth=(x-3)\ units}$