Question

Area of rectangle length is 40cm and diagonal is 41cm

Answer 1

Answer:

Solution :-

Let ABCD is a rectangle, in which length AB = 40 cm, and a diagonal AC = 41 cm.

In rectangle each angle is of 90°.

$\boxed{So, \:angle \:ABC = 90°}$

$ac {}^{2} = ab {}^{2} + bc {}^{2} \\ \\ (41) {}^{2} = (40) {}^{2} + bc {}^{2} \\ \\ 1681 - 1600 = bc {}^{2} \\ \\ 81 = bc {}^{2} \\ \\ 9 {}^{2} = bc {}^{2} \\ \\ bc = 9cm$

Hence , Breadth of rectangle = 9cm

Now, Perimeter of rectangle = 2 (length + breadth).

=> 2(40 + 9)cm

=> 2 × 49 cm.

$\tt\huge{Hence,Perimeter\: of\: rectangle \:is \:98 cm}$

Answer 2

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