Area of rectangle using diagonal 17 and perimeter 46
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Answered by
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Step-by-step explanation:
length of rectangle be l
breadth of rectangle be b
perimeter = 2(l+b)
46 = 2 (l+b)
23 = l+b
and it is given that it has a diagonal that means that it is divided into triangle in which diagonal is a hypotenuse
l² + b² = 17²
(l+b)² - 2lb = 289
Put l+b = 23
23² - 2lb = 729
529 - 289 = 2lb
240/2 = lb
120 = lb
Since l and b are its lengths and breadths respectively so lb is its area
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