Area of rectangle with perimeter equal to 12 units
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Perimeter of rectangle=2(L+B)
12=2(L+B)
L+B=6
L=6-B
Area = L×B
=(6-B)B
Area(A) = 6B-B²
Derivating with respect to B,
0=6-2B
B=3
Therefore, L=6-B=6-3=3
Therefore, Area = 3×3 = 9
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