Question

area of rectangular field whose perimeter is (a² - 19a + 90)sq m. find the breadth if length is (a - 9) m. hint ( a² - 19a + 90) ÷
(a - 9)​

Answer 1

Answer:

Breadth of rectangle= (a-10)m

Step-by-step explanation:

We know that,  

area of rectangle = length x breadth

        ($a^{2}-19a+90$)  = $(a-9)$ x breadth

So, breadth will be the quotient on dividing $(a^{2}-19a+90)$ by $(a-9)$.

                  $a$$-10$             <-------quotient (breadth of rectangle)

     $(a-9)$$\sqrt{a^{2}-19a+90 }$

               _$-a^{2}+9a$____

                         $-10a$$+90$

               _____$+10a-90$___

               __________0_____