Question

Area of rhombas is 96sq.cm . One of the diagonal is 12cm find the length of its other​

Answer 1

Answer:

answer is 16cm

hope it helps

Answer 2

$\underline{\underline{\huge{\blue{\tt{\textbf Given :-}}}}}$

Area of a rhombus = 96 cm²

Length of one diagonal = 12 cm

$\underline{\underline{\huge{\blue{\tt{\textbf find :-}}}}}$

length of other diagonals=??

$\underline{\underline{\huge{\blue{\tt{\textbf solution :-}}}}}$

As we know that area of a rhombus is given by,

• Area = pq/2

Where,

p and q are diagonals of a rhombus.

Therefore,

let's say, Length of one diagonal

= 12 cm = p

• area = pq/2
• 96=12q/2
• ∴ q = 16 cm

Now,

As the diagonal bisect the rhombus into four right angle triangle.

• ∴ one side = 16/2 = 8 cm

• other side = 12/2 = 6 cm

Now by using,

Pythagoras theorem,

Hypotenuse = √6²+8²= 10 cm

• Hence, length of each side of the given rhombus = 10 cm