Question

Area of rhombus (in sq cm) having length of diagonals as 16 cm and 18 cm is ​

Answer 1

Answer:

144cm^2

Given:

Diagonal 1(d1) = 16cm

Diagonal 2(d2) = 18 cm

Step-by-step explanation:

Area of Rhombus(A)= {(diagonal 1*diagonal 2)}/2

Therefore,

A=d1/d2

A= (16*18)/2

A=144cm^2

Answer 2

Answer:

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Area of rhombus (in sq cm) having length of diagonals as 16 cm and 18 cm is

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• Diagonal 1 = 16 cm

• Diagonal 2 = 18 cm

Area of Rhombus = ½ × diagonal 1 × diagonal 2

➡️ ½ × 16 × 18

➡️ 8 × 18

➡️ 144 cm²