Question

Area of rhombus is 24 cm square if one of its diagonal is 6 CM then its perimeter is

Answer 1

Answer:

area of rhombus=1/2*d1*d2

24=1/2*6*d2

48=6d2

d2=48/6

d2=8cm

if d1=6cm,d2=8cm

a diagonal of a rhombus bisect each other at right angle,                      then by pythogoras theorem,

side{2}=(6)2=(8)2

side(2)=36=64

side(2)=100

side=10

perimeter=4*side

perimeter=4*10

perimeter=40

Step-by-step explanation:

Answer 2

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