Question

area of rhombus is 24cm^2 and one diagonal is 6 cm then finds its perimeter.​

Answer 1

Given :-

area of rhombus = 24 cm^2

diagonal of rhombus = 6 cm

$area \: \: = \: \: \frac{1}{2} \times d1 \: \: \times d2$

$24 \: \: = \: \: \frac{1}{2} \times 6 \times d \\ \\ 24 = 3 \times d \\ \\ d \: \: = \: \: 8 \: cm$

perimeter of rhombus = 4s

= 4 (10) = 40