Math, asked by aaryabhagat555, 4 months ago

Area of rhombus is 50√3 square units . One of its diagonal is 10 units then find length of its other diagonal , length of side of rhombus and its perimeter​

Answers

Answered by reddysaritham
25

Step-by-step explanation:

Answer

Diagonals of a rhombus bisect each other at right angles.

Let ABCD be the rhombus, Diagonal AC=16 cm and side AB=10 cm.

In right △AOB, AB=10 cm, AO=8 cm

By Pythagoras theorem, AB2=AO2+BO2

⇒102=82+BO2

⇒BO2=100−64=36

∴BO=6cms

Diagonal BD=2×6=12cm

Area of Rhombus=21×(productofthediagonals)

=21×16×12=8×12=96sq.cm

Hence length of other diagonal =12 cm; 

And Area of rhombus =96sq.cm

Answered by Kanagalakshmi201
7

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