Area of rhombus is 50√3 square units . One of its diagonal is 10 units then find length of its other diagonal , length of side of rhombus and its perimeter
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Diagonals of a rhombus bisect each other at right angles.
Let ABCD be the rhombus, Diagonal AC=16 cm and side AB=10 cm.
In right △AOB, AB=10 cm, AO=8 cm
By Pythagoras theorem, AB2=AO2+BO2
⇒102=82+BO2
⇒BO2=100−64=36
∴BO=6cms
Diagonal BD=2×6=12cm
Area of Rhombus=21×(productofthediagonals)
=21×16×12=8×12=96sq.cm
Hence length of other diagonal =12 cm;
And Area of rhombus =96sq.cm
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