Question

area of rhombus is 96 CM square and its diagonal is 16 cm then its height is

Answer 1

Rhombus area = 1/2×d1×d2 ATQ , 1/2×16×y=96, y=12 , and we also know that diagonal bisect each other so side will be finded by pythagorus side =root of 16*16+12*12= 20 so as rhombus is a parallelogram thus its area =base ×height thus 96=20×y ,y=4.8 cm

Answer 2

Rhombus area = 1/2×d1×d2

(d1=d2=diagonal 1 and 2)

1/2×16×y=96》 y=12 (y=height)

we know that diagonal bisect each other so side will be finded by pythagorus side =root of 16*16+12*12= 20 so as rhombus is a parallelogram thus its area =base ×height thus 96=20×y ,y=4.8 cm