area of rhombus is half a square -bsquare one of diagonal is a+b other diagonal is
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let the diagonals of a rhombus are d1, d2
d1=a+b
d2=?
area of the rhombus = d1d2/2-----(1)
but given area of rhobus = a²- b²
= (a+b)(a-b)----(2)
(1) = (2)
d1d2/2 = (a+b)(a-b)
(a+b) *d2 = (a+b)(a-b)
d2 = (a+b)(a-b)/(a+b)
d2 = a-b
therfore second diagonal = (a-b)
d1=a+b
d2=?
area of the rhombus = d1d2/2-----(1)
but given area of rhobus = a²- b²
= (a+b)(a-b)----(2)
(1) = (2)
d1d2/2 = (a+b)(a-b)
(a+b) *d2 = (a+b)(a-b)
d2 = (a+b)(a-b)/(a+b)
d2 = a-b
therfore second diagonal = (a-b)
mysticd:
(a+b)*d2/2=(a+b(a-b)/2
aftter cancellation
d2= (a-b)
what is the forumla for the area of rhombus
area of rhombus = d1d2/2 = half of product of the diagonals
given d1 = a+b, d2 = ? A = (a^2- b^2)/2
d1d2/2 =(a^2-b^2)/2
(a+b)d2/2 = (a^2-b^2)/2
d2= [(a+b)(a-b)*2]/[2*(a+b)]
d2=a-b
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