area of rhombus whose diagonals are 24cm each of which side measures 20cm is
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1
Since the diagonals bisect at 90°. we will use this to calculate the length of other diagonal.
Area of Diagonal = D1 x D2 /2
We know D1=24 cm
To find the length of another diagonal=:
SIDE²= (D1/2)² + (D2/2)²
20²= 12² + (D2/2)²
(D2/2)²= 400-144
(D2/2)²=256
(D2/2)=16
D2= 32
Area= D1 * D2 / 2= 384 cm²
Area of Diagonal = D1 x D2 /2
We know D1=24 cm
To find the length of another diagonal=:
SIDE²= (D1/2)² + (D2/2)²
20²= 12² + (D2/2)²
(D2/2)²= 400-144
(D2/2)²=256
(D2/2)=16
D2= 32
Area= D1 * D2 / 2= 384 cm²
Answered by
0
Answer:
A = 384cm²
a = Side = 20cm
p = Diagonal = 24 cm
a = pq / 2
a = p² + q² / 2
a = 1 / 2 p √4² - p²
= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³
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