Question

area of rhombus whose diagonals are 24cm each of which side measures 20cm is

Answer 1

Since the diagonals bisect at 90°. we will use this to calculate the length of other diagonal.

Area of Diagonal = D1 x D2 /2

We know D1=24 cm


To find the length of another diagonal=:

SIDE²= (D1/2)²  + (D2/2)²
20²=   12²  + (D2/2)²
(D2/2)²= 400-144
(D2/2)²=256
(D2/2)=16

D2= 32

Area= D1 * D2 / 2=  384 cm²

Answer 2

Answer:

A = 384cm²

a = Side = 20cm

p = Diagonal = 24 cm

a = pq / 2

a = p² + q² / 2

a = 1 / 2 p √4² - p²

= 1 / 2 • 24 • √ 4.20² - 24² = 384 cm³