Question

Area of rhombus with length of diagonals are 12 and 16 cm

Answer 1

Answer:

area of rhombus = pq/2

=.12×16/2

area of rhombus = 96

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Answer 2

The sides of Rhombus are 10 cm.

$\underline{\bf{Explanation\::}}$

As the question mentioned there are 2 diagonals

The length of the first diagonal is 12 cm, whereas the length of the second diagonal is 16 cm

We divide the rhombus into 4 parts, let us take part 1:

As the diagram shown below, using Pythagoras theorem we find s

Now as we know that BD = 16 cm and AC = 12 cm; therefore to find S

We use,

$\left(\frac{B D}{2}\right)^{2}+\left(\frac{A C}{2}\right)^{2}=S^{2}$

Putting the values of BD and AC, we get,

$\left(\frac{16}{2}\right)^{2}+\left(\frac{12}{2}\right)^{2}=S^{2}$

$(8)^{2}+(6)^{2}=S^{2}$

$\sqrt{100}$

$\therefore S=10 \ \mathrm{cm}$