area of right angle triangle is 24cm sq cm if base is 8 cm find its perimeter
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½ × base × perpendicular = area
or, ½ × 8 × perpendicular = 24
or, perpendicular = (24×2)/8
or, perpendicular = 6
Now, Base²+Perpendicular² = Hypotenuse²
or, 8²+6² = Hypotenuse²
or, 64+36 = Hypotenuse²
or, Hypotenuse = √100
or, Hypotenuse = 10
Perimeter of the triangle = (base + perpendicular + hypotenuse)
= (8+6+10)cm
= 24cm
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