Question

Area of right angled triangle is 48cm².If its smallest perpendicular side is 8 cm,than find the base.Please answer with method its Important​

Answer 1

Given :-

• Area of right angled triangle = 48 cm²
• Length of smallest perpendicular = 8 cm

To find :-

• The base

According to the question,

Let,

• The base be x

➞ Area of right angled triangle = ½ × Base × Perpendicular

➞ 48 cm² = ½ × x × 8 cm

➞ 48 cm² = x × 4 cm

➞ 48 cm² ÷ 4 cm = x

➞ 12 cm = x

• So,the base of right angled triangle is 12 cm.

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MORE FORMULAS :-

• Area of rectangle = Length × Breadth
• Area of square = Side × Side
• Surface area of a cube = 6a²
• Surface area of cuboid = 2(lb + bh + hl)
• Volume of cuboid = l × b × h
• Total surface area of a hemisphere = 3πr²
• Curved surface area of a cone = πrl
• Total surface area of a cylinder = 2πr(r + h)

Answer 2

Step-by-step explanation:

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$\purple{\bigstar}$ $\text{\Large\underline{\bf{Question:-}}}$

$\mapsto$ Area of right angled triangle is 48cm².If its smallest perpendicular side is 8 cm,than find the base.Please answer with method its Important.

$\red{\bigstar}$ $\text{\Large\underline{\bf{To\ find:-}}}$

$\mapsto$ ● We have to find the base of the right angled triangle.

$\blue{\bigstar}$ $\text{\Large\underline{\bf{Given:-}}}$

$\mapsto$ ● Area of right angled triangle = 48cm².

$\mapsto$ ● Length of the smallest perpendicular = 8cm.

$\green{\bigstar}$ $\text{\large\underline{\bf{Formula\ to\ be\ used}}}$

$\pink{\bigstar}$ Area of right angled triangle = $\mathrm{\dfrac{1}{2}\ ×\ base\ ×\ perpendicular}$

$\purple{\bigstar}$ $\text{\large\underline{\bf{According\ to\ the\ question:-}}}$

$\mapsto$ Let the base of the triangle be x.

$\mapsto$ 48cm² = ½ × x × 8cm

$\mapsto$ 48cm² = x × 4cm

$\mapsto$ 48cm² ÷ 4cm = x

$\mapsto$ 12cm = x

● Hence, the required base of the right angled triangle is 12cm.

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