Question

Area of right angled triangle is 600 sq. cm. If one of its sides containing the right angle is 40 cm then find the other two sides of the triangle

Answer 1

Answer:

Step-by-step explanation:

Given base of triangle exceeds altitude by 10 cm

Let the altitude be x cm

Therefore, base = (x + 10) cm

Area of triangle = (1/2) x base x altitude

600 = (1/2) × (x + 10) × (x)

1200 = x2 + 10x

x2 + 10x - 1200 = 0

x2 + 40x - 30x - 1200 = 0

x(x + 40) - 30(x + 40) = 0

(x + 40) (x - 30) = 0

(x + 40) = 0 or (x - 30) = 0

Therefore x = -40 or x = 30

But x cannot be negative

Hence x = 30 cm

That is altitude = 30 cm

Base = 40 cm