Question

area of rohmbus is 120 cm ^2 and it's one diagonal is 24 . then find each side . please don't spam . ​

Answer 1

Answer:

Area of rhombus A = (d1d2)/2 =>

120 = (24)(d2)/2 => d2 = 10 cm.

Length of side of rhombus s = Hypotenuse of right triangle h with half the lengths of the two diagonals d1, d2 as the other two sides at right angles. h^2 = (d1/2)^2 + (d2/2)^2 => h^2 = (24/2)^2 + (10/2)^2 = 12^2 + 5^2 => h = 13 cm => length of side of rhombus s = 13 cm.

Answer 2

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$\textsf{Area of rhombus A = (d1d2)/2}$

$\textsf{=> 120 = (24)(d2)/2}$

$\textsf{=> d2 = 10 cm.}$

$\texttt{Explanation:-}$

Length of side of rhombus s = Hypotenuse of right triangle h with half the lengths of the two diagonals d1, d2 as the other two sides at right angles.

h^2 = (d1/2)^2 + (d2/2)^2

$\textsf{ => h² = (24/2)² + (10/2)²}$

$\textsf{= 12² + 5²}$

$\textsf{ => h = 13 cm}$

$\textsf{=> length of side of rhombus = 13 cm.}$

Hence, length of all sides of rhombus is 13cm.