English, asked by XxItzSrutixX, 3 days ago

Area of Sector of a circle of Radius 15 cm is 30 cm².
Find A Length of the arc of a sector .​

Answers

Answered by meetdchaudhari2006
3

Explanation:

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Answered by Evyaan7
3

Area of sector of circle =30 cm

Area of sector of circle =30 cm 2

Area of sector of circle =30 cm 2

Area of sector of circle =30 cm 2 radius of circle =15 cm

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector =

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ =

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A =

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×15

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 =

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr=

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15×

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 15

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152

Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152 Length of arc =4 cm

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