Area of Sector of a circle of Radius 15 cm is 30 cm².
Find A Length of the arc of a sector .
Answers
Explanation:
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Area of sector of circle =30 cm
Area of sector of circle =30 cm 2
Area of sector of circle =30 cm 2
Area of sector of circle =30 cm 2 radius of circle =15 cm
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector =
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ =
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A =
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×15
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 =
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr=
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15×
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 15
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152
Area of sector of circle =30 cm 2 radius of circle =15 cmArea of sector = 360θ ×πr 2 360θ = πr 2 A = π×15×1530 = 15π2 now length of arc =2πr= 360θ =2π×15× 152 Length of arc =4 cm