Question

area of sector of angle 60 degree of a circle with radius 10 cm is

Answer 1

Hope you will understand

Answer 2

Area of sector is $\bf 52 \frac{8}{21} \:cm^2$

Option (b) is correct.

Given:

• A sector of angle 60° of a circle with radius 10 cm.

To find:

• Find the area of sector.

Solution:

Formula to be used:

Area of sector:$\bf \frac{ \theta}{360} \times \pi \: {r}^{2}$

here,

theta is angle of sector and r is radius.

Step 1:

Write the given values.

$\theta = 60^{\circ}$

$r = 10 \: cm$

Step 2:

Put the values in formula.

$Area = \frac{60}{360} \times \frac{22}{7} \times ( {10)}^{2}$

or

$Area = \frac{1}{6} \times \frac{22}{7} \times 100$

or

$Area = \frac{1}{3} \times \frac{11}{7} \times 100$

or

$Area = \frac{1100}{21} \: cm^2$

Because it is an improper fraction, so divide to convert into mixed fraction.

$21 \: )1100 \: (52 \\ 105 \\ - - - - - \\ 50 \\ 42 \\ - - - - - \\ 8 \\ - - - - -$

So,

$\frac{1100}{21} = 52 \frac{8}{21} \\ \:$

Thus,

Area of sector is $\bf 52 \frac{8}{21} \:cm^2$

Option (b) is correct.

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