Question

area of shaded region​

Answer 1

Step-by-step explanation:

Consider ∆ ALM,

LM is base = 4m

AL is height = 3 m

Area of triangle = 1/2 ×b×h

= 6 sq m

Now consider ∆MNC,

NC is base = 4m

MN is height = 3m

Area of triangle = 1/2 ×b ×h

= 6 sq cm

Now!

Area of shaded region = A(∆ALM)+A(∆MNC)

= 6 + 6

= 12 sq m

So area of shaded region is 12 sq m!

Answer 2

Answer:

area of ALM IS 6m and mnc is 6m

Step-by-step explanation:

by hypotenuse theorem

AMsquare =al square +lmsquare

5square=3square+lm square

25=9+lm square

lm sqare=16

lm=4m

area of triangle is l*b/2

=3*4/2

=12/2

=6m

///ly

mcsquare =nc square +mnsquare

5square=4square+lm square

25=16+lm square

25-16=lm square

lmsquare=9

lm =3

area of triangle is l*b/2

=3*4/2

=12/2

=6m

i hope this will help you