Question

area of similar triangle are in the ratio 81:64 for equilateral triangle. find the perimeter of triangle ​

Answer 1

Step-by-step explanation:

Let ∆ABC (whose sides are a,b and c)and ∆ PQR (whose sides are p,q and r) are

two similar triangles , therefore

a/p = b/q = c/r = k(let) . , thus , a=pk , b=qk. and c=rk.

Given that:-

(a+b+c)/(p+q+r)=9/16. , ( putting a=pk , b=qk and c= rk.)

or. k.(p+q+r)/(p+q+r)= 9/16.

or. k=9/16.

Area of ∆ABC/Area of ∆PQR = (a/p)^2=(b/q)^2=(c/r)^2=k^2.

= (9/16)^2.

=81/256. or. 81 : 256. , Answer.