area of sq 400 cm and lenghth is 4cm find its breath
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Step-by-step explanation:
Let the sides of Square A be “x” cm,
and the sides of Square B be “x + 4” cm.
Hence, sum of area of two squares A abd B are :
x^2 + (x +4)^2 = 400
x^2 + (x^2 + 8x + 16) = 400
2x^2 + 8x + 16 = 400
x^2 + 4x + 8 = 200
x^2 + 4x - 192 = 0
(x - 12)(x + 16) = 0
therefore, x = 12, or -16.
Substitute x = 12 into first equation, we have
144 + (16)^2 = 400
144 + 256 = 400 QED.
dimension of Square A is 12cm
dimension of Square B is 16cm
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