Question

Area of sqiare field is 60025 m aman/cycles along its boundary at 18km/hr in/how much time will he return to the starting point

Answer 1

Answer: the correct answer to this question is 3 min. 16 sec.

Step-by-step explanation:

The area given is 60025 sq. m

By using the area formula

S × S. = Area of square

From this we get the value of S = 245m

अब S से हम उस मैदान का perimeter. निकालेंगे जो आयेगा 980m.

क्योंकि वह आदमी 18km/h की रफ्तार से साईकल चला रहा था जिसका मतलब है 5m/s

से।

Now by using the formula

S = D. ×. T

We get the time as 196sec.

Which is equal to

3 Min 16 Sec

Answer 2

Given

✭ Area of a square field is 60025 m²

✭ A man cycle around its boundary will a speed of 18 km/h

$\displaystyle\large\underline{\sf\blue{To \ Find}}$

◈ How much time would he spend to complete one round?

$\displaystyle\large\underline{\sf\gray{Solution}}$

So here we may first find the perimeter of the square and then use he formula for speed, interchange the Values and get our Time!!

━━━━━━━━━

$\underline{\bigstar\:\textsf{According to the given Question :}}$

Area of a square is given by,

$\displaystyle\underline{\boxed{\sf Area_{square} = Side^2}}$

Area = 60025 m²

Substituting the values,

$➝ \displaystyle\sf Area = Side^2Area=Side </p><p>2$

$➝ \displaystyle\sf 60025 = Side^260025=Side </p><p>2$

$➝ \displaystyle\sf \sqrt{60025} = Side </p><p>$

=Side

$➝ \displaystyle\sf \purple{Side = 245 m}Side=245m$

Then the perimeter of the field will be,

$➢ \displaystyle\sf Perimeter_{Square} = 4\times \: Side$

$➢ \displaystyle\sf Perimeter = 4\times 245$

$➢ \displaystyle\sf \green{Perimeter = 980 \ m}$

Now we shall convet the speed to m/s

$»» \displaystyle\sf 18 \ km/s = 18\times \dfrac{5}{18}18 km/$

»»

$\displaystyle\sf \orange{Speed = 5 \ m/s}$

Now the speed of a body is given by,

$➳ \displaystyle\sf Speed = \dfrac{Distance}{Time}$

So here,

$➳ \displaystyle\sf Time = \dfrac{Perimeter}{Speed}$

Substituting the values,

$›› \displaystyle\sf Time = \dfrac{980}{5}$

$</p><p>›› \displaystyle\sf \pink{Time = 196 \ sec}</p><p>$

$\displaystyle\therefore\:\underline{\sf Time \ taken \ will \ be \ 196 \: sec}∴$