Question

Area of square ABCD is 144 cm. If side of another square PQRS is 1 cm greater than
square ABCD find its area. ?????

Answer 1

Step-by-step explanation:

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Answer 2

$\sf\large\red{\underline{ given : }}$

• Area of 1st square ABCD is 144cm².
• Side of 2nd square is 1cm greater than 1st square.

$\\ \sf\large\red{\underline{ to \: find : }}$

• Area of 2nd square.

$\\ \sf\large\red{\underline{ to \: know : }}$

♣Area of square = side²

$\\ \sf\large\red{\underline{solution : }}$

We know ,

Area of 1st square ABCD is 144cm².

So, according to formula ,

$\sf\large\red{\underline{ }}144 = {side}^{2} \\ \\ \sf\large\red{\underline{ }}side \: = \sqrt{144} \\ \\ \sf\large\red{\underline{ }} = > side \: = 12cm$

We know , the 2nd square has the side 1cm more than 1st square .

∴ Side of 2nd square = 13cm

Area of 2nd square with side 13cm will be...

$\sf\large\red{\underline{ }}area \: = {side}^{2} \\ \\ \sf\large\red{\underline{ }}area \: = {13}^{2} \\ \\ \sf\large\green{\underline{ area \: = 169 {cm}^{2} }}$

∴ The answer is 169cm².