Question

Area of square field is 50625 m sq. A man cycles along its boundary at 18km/h. In how much time will he return at the starting point.(class viii)

Answer 1

Hi ,

Let length of the square field = a m

Area of the field = 50625 sq m

a² = 225m × 225 m

a = 225 m

Distance travelled by cycle( P )

= Perimeter of square field

= 4a

= 4 × 225 m

= 900 m

Distance ( d ) = 900 m

Speed ( s ) = 18 km / hr

= 18× (1000/60)m/mi

= 300 m / mi

Let Time = t hr

t = d/s

= 900 / 300

= 3 mi

Therefore ,

Time taken to reach the starting

point ( t ) = 3 mi

I hope this helps you.

: )

Answer 2

Answer:

3 minutes

Step-by-step explanation:

hi friends..

the area of square field is 50625s. metre (given)

each side of square=√50625m²

=225m

According to the question

the man rides the cycle along the the boundary. (given)

hence, perimeter of square=4×225m

=900m

so, distance=900m

speed =18km/hr

18×1000/60

300 minutes

we know that time=distance/speed

= 900/300

3minutes

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