Question

area of teapezium is 12sq.m if it's height is 3m find the sum of its parallel sides

Answer 1

HEY FRIEND

HERE IS YOUR ANSWER

$area \: of \: trapezium = \frac{1}{2} \times height \times sum \: of \: parallel \: sides \\ \\ 12 = \frac{1}{2} \times 3 \times sum \: of \: parallel \: sides \\ \\ \frac{12 \times 2}{3} = sum \: of \: parallel \: sides \\ \\ \frac{24}{3} = sum \: of \: parallel \: sides \\ \\ 8 = sum \: of \: parallel \: sides$

so the sum of parallel sides is 8m

Answer 2

Heya ✋

Let see your answer !!!!!

Given that

Area of a trapezium = 12m^2

Height = 3m

Sum of all parallel sides = ?

Solution

Area of a trapezium = 1/2 × sum of parallel sides × height

=> 12 = 1/2 × sum of parallel sides × 3

=> 12 × 2/3 = sum of parallel sides

=> sum of parallel sides = 8m








Thanks :))))