Question

Area of the ABC whose vertices are A(0,4) B(3,0) c(4,6) is​

Answer 1

Answer:

Area of ∆ABC =1/2[X1(y2-y3)+X2(y3-y1)+x3(y1-y2)]

=1/2[0(0-6)+3(6-4)+4(4-0)]

=1/2[0×(-6)+3×2+4×4]

=1/2(0+6+16)

=1/2×22

=11unit²