Question

Area of the base of a cylender as 616 cm², and its neight is 25cm. Find its CSA, TSA and volume. ​

Answer 1

Given ,

•Area of the base of the cylinder = 616 cm².

• Height of the cylinder (h) = 25 cm.

Let radius be → r

We know that ,

$\underline \bold{Base \: area \: of \: cylinder = πr²}$

$\implies \: 616 = \pi {r}^{2}$

$\bold{ \implies \: 616 = \frac{22}{7} \times {r}^{2} }$

$\bold{ \implies \: {r}^{2} = \frac{616}{22} \times 7 }$

$\bold{ \implies \: {r}^{2} = 196 }$

$\bold{ \implies \: {r}^{2} = {14}^{2} }$

$\bold{ \implies \: \boxed{ \bold{{r}^{} = {14} \: \: cm. }}}$

Now,

$\underline \bold{★ \: CSA \: o f \: the \: cylinder = 2πrh}$

$\implies \bold{CSA \: of \: the \: cylinder = 2 \times \frac{22}{7} \times 14 \times 25}$

$\implies \boxed{\bold{CSA \: of \: the \: cylinder = 2200 \: \: {cm}^{2} }}$

$\underline \bold{★ \: TSA \: of \: the \: cylinder = 2πr(r+h)</p><p>}$

$\implies \bold{TSA \: of \: the \: cylinder = 2 \times \frac{22}{7} \times 14(14 + 25)</p><p>}$

$\implies \bold{TSA \: of \: the \: cylinder = 2 \times \frac{22}{7} \times 14 \times</p><p>}$

$\implies \boxed{\bold{TSA \: of \: the \: cylinder =3432 \: \: {cm}^{2} }}$

$\underline \bold{★ Volume \: of \: the \: cylinder = πr²h}$

$\implies \: \bold{Volume \: of \: the \: cylinder = \frac{22}{7} \times {14}^{2} \times 25 }$

$\implies \: \bold{Volume \: of \: the \: cylinder = \frac{22}{7} \times 14 \times 14\times 25 }$

$\implies \: \boxed{\bold{Volume \: of \: the \: cylinder = 15400 \: \: {cm}^{3} }}$