Question

Area of the circle inscribed in a square of diagonal 62 cm (in sq. Cms) is

Answer 1

Here is your answer

$why \: is \: the \: length \: of \\ \: the \: diagonal = \sqrt{2} a$

Now let us consider the triangle

ABC

We know that it is a right angle triangle and the length of each side is "a".

By applying Pythagoras's theorem we know,

${ab}^{2} + {ac}^{2} = {bc}^{2} \\ \implies {bc}^{2} = {a}^{2} + {a}^{2} \\ \implies2 {a}^{2} = {bc}^{2} \\ \implies \: bc = \sqrt{2 {a}^{2} } \\ \implies bc = \sqrt{2} a$