Question

Area of the four walls of a room is 240 m². The
length and breadth are in the ratio 3:2 and the
height of the room is 3m find the area of the
floor.​

Answer 1

Answer:

Step-by-step explanation:

CSA OF ROOM =240

let length=2x

    breadth =3x

we know CSA = 2(l+b)h=240

         6(5x)=240

       5x=40

          x=8

length=24

breath+16

Answer 2

Given:

The area of the four walls of a room is 240 m²

The ratio of the length and breadth=3:2

Height of the room=3m

To find:

The area of the floor

Solution:

The area of the floor is 384 $m^{2}$.

We can find the area by following the steps given below-

We know that the area of the four walls of a room forms the curved surface area.

Since a room is in the shape of a cuboid, the area of four walls=Curved surface area of a cuboid

We are given that the ratio of the length and breadth of the room is 3:2.

Let the length of the room be 3X and the breadth of the room is 2X.

The area of four walls=240$m^{2}$

The area of four walls=2(length+ breadth)×height

On putting the values, we get

240=2(3X+2X)×3

240=6×5X

240=30X

240/30=X

X=8m

So, the length of the room=3X=3×8=24m

The breadth of the room=2X=2×8=16m

Now, the area of the floor is the area of a rectangle.

So, the area of the floor=Length of the room×breadth of the room

=24×16

=384 $m^{2}$

Therefore, the area of the floor is 384 $m^{2}$.