Area of the four walls of a room is 660sq.m and its length is twice the breadth. If the height of the room is 11m, then the area (in sq.m.) of its floor is -----
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Answered by
0
Answer:
200 sq.m.
Step-by-step explanation:
let breadth= b
length= l= 2b given by
hight= h =11
according to the problem,
(l×11×2)+(b×11×2)=660
(2×b×11×2)+(b×11×2)=660
22×b×(2+1)=660
66×b=660
b=10
Then the area of floor is l×b =2×b×b=2×10×10=200 sq.m
which is required.
Answered by
2
Answer:
200 sq.m.
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