Question

Area of the four walls of a room is 660sq.m and its length is twice the breadth. If the height of the room is 11m, then the area (in sq.m.) of its floor is -----​

Answer 1

Answer:

200

Step-by-step explanation:

let l be the length,b be the breadth and h be the height of the room

(2*l*h) + (2*b*h) = 660

i.e. 2*h*(l+b) = 660

i.e. 2*11*(2b+b) = 660

i.e. 3b = 30

hence, b = 10

area of floor = l*b=2b*b=20*10=200

Answer 2

Answer:

Given :

Area of 4 walls= 660 m²

Height (h)= 11 m

Let the width be = b m

Length (1)= 2b m

Area of 4 walls of a room = 2(l+b)xh

660 = 2 (2b+ b ) × 11

660 = 2(3b) x11

3b = 660 / 11× 2= 60/2=30

3b = 30

b= 30/3= 10

b= 10 m

L = 2b = 2x 10= 20 m

L = 20 m

Area of ceiling = 1 x b

Area of ceiling= 20 x 10 = 200 m²

Hence, the area of ceiling is 200 m²

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