Question

Area of the greatest circle of the circle constructed on the sides of a right triangle, taking these sides as diameters, of the two smaller sides are 1.5 cm and 2 cm, is

Answer 1

Answer:answer is pi because daimeter is 2 so radius is 1

Step-by-step explanation:

Answer 2

Given: A circle is constructed on the sides of a right triangle, taking these sides as diameters, of the two smaller sides are 1.5 cm and 2 cm.

To find: The area of the circle.

Solution:

The right-angled triangle is constructed inside the circle in such a way that the hypotenuse of the triangle forms the diameter of the circle. Since the length of the perpendicular and the base is given, the length of the hypotenuse can be calculated using the Pythagoras theorem.

$hypotenuse = \sqrt{(2)^{2} + (1.5)^{2}}$

                  $= 2.5 cm$

Both the hypotenuse of the triangle and the diameter of the circle is 2.5 cm in length. The radius of the circle is half of its diameter, which is 1.25 cm. Now, the area of the circle is calculated using the following formula.

$Area = \pi r^{2}$

        $= \frac{22}{7} * (1.25)^{2}$

        $= 4.91 cm^{2}$

Therefore, the area of the circle is 4.91 cm².