Math, asked by Jessica7000, 1 year ago

Area of the largest triangle that can be inscribed in a semicircle of radius2cm

Answers

Answered by chandraprakashsahu
1

Answer:


Step-by-step explanation:

Construct a circle of radius 2 cm as in the figure that I have clipped. In this circle AOB is the semicircle where AB is diameter. Now draw the perpendicular bisector of AB as I have drawn in the figure and let it intersect the circle at a point and name that point as l have named as O.join AO and BO you will get dimensions 2.8cm and 2.8cm.

Now area of triangleAOB

Angle AOB is 90°{angle in semicircle}

Area=1/2 x base x height

=1/2 x 2.8 x 2.8

=1.4 x 2.8

=3.92 cm^2

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Answered by Jiya0071
1

Answer:

Hence, Area of circle will be = π(radius)² = π(r/2)² = ( πr²/4) units²

Attachments:
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