Area of the largest triangle that can be inscribed in a semicircle of radius2cm
Answers
Answered by
1
Answer:
Step-by-step explanation:
Construct a circle of radius 2 cm as in the figure that I have clipped. In this circle AOB is the semicircle where AB is diameter. Now draw the perpendicular bisector of AB as I have drawn in the figure and let it intersect the circle at a point and name that point as l have named as O.join AO and BO you will get dimensions 2.8cm and 2.8cm.
Now area of triangleAOB
Angle AOB is 90°{angle in semicircle}
Area=1/2 x base x height
=1/2 x 2.8 x 2.8
=1.4 x 2.8
=3.92 cm^2
Attachments:
Answered by
1
Answer:
Hence, Area of circle will be = π(radius)² = π(r/2)² = ( πr²/4) units²
Attachments:
Similar questions