Area of the lawn 154 square metres. Find the circumstances
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Area of a circle A=πr2, where r is the radius.
Given A=154,
⇒154=π⋅r2
⇒r2=154π=49.02
⇒r=√49.02=7.00
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a=154
area of circumstances is πr² then
A=πr²
now a=154
154=πr²
now 154*π=r²
π=3.14 or 22/7
154×7/22=49
now r²=49
r=7
area of circumstances is πr² then
A=πr²
now a=154
154=πr²
now 154*π=r²
π=3.14 or 22/7
154×7/22=49
now r²=49
r=7
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