area of the path around a square field is 425 metre square find the width of the path if the side of square is 40 metre
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Let the width of the path be x m.
Now, according to the question
(40 + 2x)^2 - 40^2 = 425
40^2 + 160x + 4x^2 - 40^2 = 425
4x^2 + 160x - 425 = 0
(2x)^2 + 2(2x)(40) +1600 - 2025 = 0
(2x + 40)^2 = 2025
2x + 40 = +- 45
x = 5/2, -85/2
Since it can't be negative
So, the required width of the path is 5/2 m or 2.5 m
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