Question

area of the polygon.. please help me

Answer 1

$\mathsf{\huge{Question}}$

Find area of the polygon.

$\mathsf{\huge{Answer}}$

First of all we will find the area of the triangle AED.

Given that,

$h_{1}$ = 8cm

ED = 6cm

BC = 12cm

$h_{2}$ = 13 cm

$\bold{By\:using\:the\:following\:formula}$ : -

$\frac{1}{2} \times base \times height$

$\frac{1}{2} \times 6cm \times 8cm$

= $24 cm^2$

$\bold{So,\:the\:area\:of\:triangle\:AED\:is\:24\:cm^2}$

Now, we have to find the area of the trapezium EDBC.

By using the following formula,

$\frac{1}{2} \times (sum of || sides) \times height$

= $\frac{1}{2} \times (ED + BC) \times 13cm$

= $\frac{1}{2} \times (6cm+12cm) \times 13cm$

= $45cm^2$

$\bold{So,\:the\:area\:of\:trapezium\:EDBC\:is\:24cm^2}$

Now, for the total area of the polygon, we have to add the area of both trapezium and triangle.

Total area = area of trapezium + area of triangle.

Total area = $45cm^2 + 24cm^2$

Total area = $69cm^2$

$\bold{Therefore,\:the\:total\:area\:of\:the\:polygon\:is\:69cm^2}$