Question

Area of the quadrilateral ABCD in which ∠ ABC = 90°
and ∠ ACD = 90° and BC = 24 cm, AC = 25 cm and
AD = 313 cm is
(A) 2948 cm2 (B) 1984 cm2
(C) 4948 cm2 (D) 3984 cm2

Answer 1

Step-by-step explanation:

(BD)

2

=(AB)

2

+(AD)

2

BD=

(32)

2

+(24)

2

BD=40cm

ΔABD=

2

1

×AB×DB

= 384cm

2

For ΔBCD,

S =

2

a+b+c

=

40

40+52+52

=72cm

=

72(72−40)(72−52)(72−52)

=

72×32×20×20

= 960cm

2

Area of ABCD = 384 + 960

= 1344cm

2