Question

area of the rectangle=594m^2
length=x+5
b=x
find perimeter

Answer 1

Area of rectangle =594
Lb=594
X*x+5=594
X²+5x=594
x²+5x-594
x²+(27-22)x-594
x²+27x-22x-594
x(x+27)-22(x+27)
(x-22)(x+27)
Taking positive value
(x=22)

Perimeter =2(22+22+5)
2*49
=98

Answer 2

area of rectangle
$(l \times b)$
length=x+5
breadth=x
$(x + 5)(x) = 594 \\ {x}^{2} + 5x - 594 = 0 \\ {x}^{2} + 27x - 22x - 594 = 0 \\ x(x + 27) - 22(x + 27) = 0 \\ (x + 27)(x - 22) = 0 \\ x = 22 \\ x = - 27$
length cannot be in negetive so x = 22cm
breadth is 22 cm
length is 22+5=27 cm
perimeter = 2(l+b)
2(27+22)=2(49)=98 cm