Area of the rectangle is 2x²-9x-5 square unit. The possible dimension of rectangle is
length = (x+5)unit , breadth = ( 2x-1) unit
length = (x-5)unit , breadth = ( 2x+1) unit
length = (2x-5)unit , breadth = ( x+1) unit
length = (x-3)unit , breadth = ( 2x+1) unit
plz plz tell the correct answer
Answers
Given :-
Given that, 2x² - 9x - 5 units² is the area of a rectangle.
To find :-
We have to find the possible dimensions of the rectangle.
Solution :-
- 2x² - 9x - 5 units² is the area of the rectangle.
- This is in the form of a quadratic equation.
- We know that, Area of rectangle = Length × Breadth.
- So, we shall find the factors of the given equation by splitting the middle term.
- The factors that we get are the possible dimensions of the rectangle.
➝ 2x² - 9x - 5
➝ Product of -5 and 2x² is -10x².
➝ Sum of -10x and x is -9x.
➝ So, -9x can be written as -10x + x.
➝ 2x² - 10x + x - 5
➝ 2x ( x - 5 ) + 1 ( x - 5 )
➝ ( 2x + 1 ) ( x - 5 )
〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️
Therefore, the dimensions of the rectangle whose area is 2x² - 9x - 5 units² are :
- Length = ( x - 5 ) units
- Breadth = ( 2x + 1 ) units
★ [Option 2] ★
Given:
Given that, 2x² - 9x - 5 units² is the area of a rectangle.
To find:-
We have to find the possible dimensions of the rectangle.
Solution:-
2x² - 9x - 5 units² is the area of the rectangle.
This is in the form of a quadratic equation.
We know that, Area of rectangle = Length × Breadth.
So, we shall find the factors of the given equation by splitting the middle term.
The factors that we get are the possible dimensions of the rectangle.
➝ 2x² - 9x - 5
➝ Product of -5 and 2x² is -10x².
➝ Sum of -10x and x is -9x.
➝ So, -9x can be written as -10x + x.
➝ 2x² - 10x + x - 5
➝ 2x ( x - 5 ) + 1 ( x - 5 )
➝ ( 2x + 1 ) ( x - 5 )
〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️〰️
Therefore, the dimensions of the rectangle whose area is 2x² - 9x - 5 units² are :
Length = ( x - 5 ) units
Breadth = ( 2x + 1 ) units
★ [Option 2] ★